1. y=x-8
2.y^2=x^2

• -1:1
  y=x-8
  (x-8)^2=x^2
  x^2+64-16x=x^2
  16x=64
  x=4;
  y=x-8
  y=4-8
  y=-4;
  y:x=-1:1
• 9 years agoHelpfull: Yes(7) No(1)
• (x-8)^2=x^2
  x^2-16x+64=x^2
  16x=64
  x=4
  y=x-8
  y=4-4=-4
  y:x=-4:4
  y:x=-1:1
• 9 years agoHelpfull: Yes(1) No(0)
• data sufficiency on 9th august
• 9 years agoHelpfull: Yes(0) No(1)
• can u post logical reasoning question
• 9 years agoHelpfull: Yes(0) No(1)
• can u post logical reasoning question
• 9 years agoHelpfull: Yes(0) No(1)
• 1:3
  x=3 => 3^2-8=1
• 9 years agoHelpfull: Yes(0) No(2)
• the question was log(e(e(e...)^1/3)^1/3)^1/3) base e was there...so ans is 1...anything to log e to base e is 1
• 9 years agoHelpfull: Yes(0) No(3)
• x^2=y^2
  x^2-y^2=0
  (x+y)(x-y)=0
  but x-y=8 acording to eqn1
  (x+y)*8=0
  x+y=0......(iii)
  now solving eqn1&3; we get 2x=8,x=4
  substituting x=4 in(iii)..we get y=-4
  so sol^n of eqn is x=4,y=-4.
  thats it
• 9 years agoHelpfull: Yes(0) No(0)
• i don't exactly remember the logical reasoning question . somewhat i remember is there were 7 girls who were recording temerature for the given whole week and sunday was not included . this all i can remember as of now .
• 9 years agoHelpfull: Yes(0) No(0)
• -1
  x-y=8, (x+y)(x-y)=0 then x=-y so y/x=-1
• 9 years agoHelpfull: Yes(0) No(0)
• ratio of y:x=-1:1
  from eq. 1 > x-y=8
  and eq 2 has x+y=0
  so x=-y
  so y=-4 and x=4
• 9 years agoHelpfull: Yes(0) No(0)
• => x^2-y^2=0;
  => (x-y)(x+y) = 0;
  => 8 (x+y) = 0; [ y= x-8]
  => 8x+8y = 0;
  => 8x = -8y;
  => (x/y )= (-8/8);
  => x/y = -1/1
  therefore ratio of x:y = -1:1
• 9 years agoHelpfull: Yes(0) No(0)
• -1:1
  y^2=(x-8)^2=x^2
  -16x+64=0
  x=4
  y=4-8=-4
  -4:4
  -1:1
• 9 years agoHelpfull: Yes(0) No(0)
• (x-8)^2=x^2==>16x=64
  x=4,y=-4
• 9 years agoHelpfull: Yes(0) No(0)
• 3:1
  y+8^2=x^2
  y=4,x=12
• 9 years agoHelpfull: Yes(0) No(0)
• Y -4,x 4
  So ans is -1
• 9 years agoHelpfull: Yes(0) No(0)
• ans: -1 . y/x = 1^2 . this gives 2 possible values of y/x. Out of it , y/x = -1 satisfies eqn 1.
• 9 years agoHelpfull: Yes(0) No(0)
• y = x - 8
  y^2 = x^2
  (x - 8)^2 = x ^ 2
  x = 4
  so y = - 4
  y : x = -4 : 4
• 9 years agoHelpfull: Yes(0) No(0)
• 1:1
  y^2/x^2=1
• 9 years agoHelpfull: Yes(0) No(1)
• (x-8)^2=x^2
  x^2+64-16x=x^2
  -16x=-64
  x=4
  then y=-4
  so ratio is -1:1
• 9 years agoHelpfull: Yes(0) No(0)
• here y^2=x^2 => (x-y)(x+y)=0 and y=x-8=> x-y != 0
  so x+y=0 => x=-y
  now from eq 2
  y=x-8
  2y=-8
  => y=-4 and x=4;
• 9 years agoHelpfull: Yes(0) No(0)
• -1:1
  x=4 & y=-4.
• 9 years agoHelpfull: Yes(0) No(0)
• ratio will be -1/1
  
• 9 years agoHelpfull: Yes(0) No(0)
• ratio is=-1:1
  y^2/x^2=1
  (x-8)^/x^2=1
  x=4
  and y=x-8
  so, y=-4
  hence ratio is -1:1
  
• 9 years agoHelpfull: Yes(0) No(0)
• ratio will be -1:1 because according to both equations the values of x and y are 4,-4
• 9 years agoHelpfull: Yes(0) No(0)
• y^2-x^2=0
  therefore (y-x)(y+x)=0
  y=x,-x
  putting in first equation
  -x=x-8
  x=4
  y=-4
  ratio is -1:1
  second root is not the valid root
  
• 9 years agoHelpfull: Yes(0) No(0)