write a prog such that take 'n' as input and print the o/p.
for example if n=3 then o/p is as folows
1
2*2
3*3*3
3*3*3
2*2
1
and if n=6, then
1
2*2
3*3*3
4*4*4*4
5*5*5*5*5
6*6*6*6*6*6
6*6*6*6*6*6
5*5*5*5*5
4*4*4*4
3*3*3
2*2
1

• #include
  int main()
  {
  int n,i,j;
  scanf("%d",&n);
  for(i=1;i
• 8 years agoHelpfull: Yes(6) No(0)
• main()
  {
  int I,o,n;
  clrscr();
  printf("enter number");
  scanf("%d",&n);
  for(o=1;o
• 8 years agoHelpfull: Yes(1) No(0)
• #include
  #include
  using namespace std;
  int main()
  {
  int n,i,j;
  coutn;
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int i,j;
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(1)
• #include
  void main()
  {
  int i,j,n;
  printf("Enter the doubling factor: ");
  
  scanf("%d",&n);
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  #include
  int main()
  {
  clrscr();
  int i, j;
  for(i=0;i=1;i--)
  {
  for(j=1;jj)
  {
  printf("*");
  }
  }
  printf("n");
  }
  getch();
  return 0;
  }
  
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  
  int main(void) {
  int n,i,j;
  scanf("%d",&n);
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  #include
  int main()
  {
  int i,j,n;
  printf("Enter no");
  scanf("%d",&n);
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(0)
• int main(int argc, char *argv[]) {
  
  int a,i,j;
  int temp;
  printf("Enter a value ");
  scanf("%d",&a);
  temp=a;
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  #include
  void main()
  {
  int i,j,row;
  clrscr();
  printf("Enter no of rows:");
  scanf("%d",&row);
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(0)