A spherical solid ball of radius 58 mm is to be divided into eight equal parts by cutting it four times longitudinally along the same axis.Find the surface area of each of the final pieces thus obtained( in mm^2) ? (where pi= 22/7)
(a) 3365pi (b) 5046pi (c)1682pi (d) 3346pi

• if you cut the sphere solid ball into 8 pieces as mentioned above each piece will look like a slice of a orange.
  therefore, surface area of each piece = curved surface area + pi*r^2
  surface area of each piece = (4*pi*r^2)/8 + pi*r^2 = 3/2 * pi* r^2 = 5046*pi
  hence answer is option b.
• 8 years agoHelpfull: Yes(26) No(1)
• Surface area of sphere = 4 pi 582 = 3364pi
  
  It is divided into 8 part by cutting it along with its axis 4 times.
  So, in each cut its area will inrease by 2 pi r2
  So in four cuts its area will increase b 4x2 pi 582 = 8 pi 582
  
  So area of each piece = (4 pi 582 + 8 pi 582) / 8 = 1.5 pi582 = 5046pi
• 7 years agoHelpfull: Yes(3) No(1)
• Required surface area= ( 4*pi*r^2)/8
  = (4*pi*58^2)/8 = 1682pi
• 8 years agoHelpfull: Yes(1) No(9)
• surface area of sphere = 4*pi*r^2
  for 1 part surface area = (1/8)*(4*pi*r^2) = 1/2*pi*r*r
  = (!/2)*pi*58*58 = 1682pi
• 8 years agoHelpfull: Yes(1) No(5)
• jasmine y did u add pi^r^2
  
• 8 years agoHelpfull: Yes(1) No(0)
• b)5056pi i think
• 8 years agoHelpfull: Yes(0) No(0)
• here 5 is the only number by which if we divide 2880 gives the perfect square
  2880/5=576
  Square root(576) = 24
  
• 8 years agoHelpfull: Yes(0) No(2)
• b option is correct
  
• 7 years agoHelpfull: Yes(0) No(0)