In a test P got 40% of the maximum marks and got 10 marks more than the pass mark. Q got 30% of maximum marks and failed by 10 marks. Find the pass mark.

• let maxM no. be x
  40x/100 - 10 = 30x/100 + 10
  40x-1000=30x+1000
  10x =2000
  x=200
  then
  p=40%of200-10=70
  q=30%of200+10=70
  pass marks=70
• 9 years agoHelpfull: Yes(0) No(0)
• 70
  let 200 be the max marks then p get 80 marks
  and q get 60 marks so passs mark will be 70 so that p had get 10 marks greater than pass marks and q had get 10 marks less than pass marks
• 9 years agoHelpfull: Yes(0) No(0)
• let x and y be the maximum marks and pass marks,
  then
  P got 40% of the maximum marks which is 10 marks more than pass marks
  according to this eq can be written as
  40x/100 = y+10 ........(1)
  Q got 30% of the maximum marks and failed by 10 marks
  equation for Q as follows
  30x/100 =y-10 ........(2)
  by solving eq (1) and eq(2)
  we get x=200 and y =70 .
  so pass marks y =70.
• 9 years agoHelpfull: Yes(0) No(0)