N%7=1
N%9=2
N%11=3
Find the value of N???

• There is a number N
  
  If N is divided by 7 the remainder is 1, it can be shown as mod operator.
  
  N%7=1
  
  N%9=2
  
  N%11=3
  
  What is N?
  
  
  the way to find the answer is the trail and error method. for that start with the 7 .check the 7+1 =8, 7*7+1=50, and 7*7*7+1=344. check the number 344 with 9 and 11 it gives the remainders 2 and 3 respectively. so 344 is the one of the required number . to calculate the remaining numbers the formula is lcm(7,9,11)*any real number + 344.
  so the answer is the numbers 693*x+344. where x=0,1,2,……
• 9 years agoHelpfull: Yes(4) No(0)
• check from the option ,it will be easier ...
• 9 years agoHelpfull: Yes(3) No(0)
• I got it through trial & error method
  
  344 % 7 = 1
  344 % 9 = 2
  344 % 11 = 3
  
• 9 years agoHelpfull: Yes(3) No(0)
• 7 ,9,11, subtract the corresponding remainders from the numbers
  until the numbers become same
  
  1st iteration
  7-1=6
  9-2=7
  11-3=8
  
  Repeat process
  2nd iteration
  6-1=5=n
  7-2=5 =n
  8-3=5=n
  
  Now as the value after subtraction becomes equal stop there
  The answer num will be
  num = ( Lcm - n)÷a
  n=final value where all the numbers become equal
  a=no of iteration
  lcm= least common multiple of all the 3 numbers
  
  Hence num = (693-5)÷2=344
• 6 years agoHelpfull: Yes(3) No(0)
• 190 is the correct answer ,check it
  190%7= 1
  190%9 = 2
  190% 11 = 3
• 9 years agoHelpfull: Yes(2) No(7)
• What are the options??
• 9 years agoHelpfull: Yes(0) No(0)
• Ans) N=344
  by this this logic in Dev-C++ programming
  
  #include
  #include
  int main()
  {
  int N;
  for(N=1;N
• 9 years agoHelpfull: Yes(0) No(0)
• Ans) N=344
  
  logic in programming:
  
  for(int N=1;N
• 9 years agoHelpfull: Yes(0) No(0)
• 344, 7*49 + 1 =344, 9*38 +2 = 344, 11*31 +3 =344
• 6 years agoHelpfull: Yes(0) No(0)
• there is no formula at all only solve by hit and trial
  344%7=1
  344%9=2
  344%11=3
• 6 years agoHelpfull: Yes(0) No(0)