Elitmus
Exam
Numerical Ability
Number System
if z=100^2-x^2,then for how many value of x, z is divisible by 6.
Read Solution (Total 9)
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- 66
because x can be negative also.
33*2=66
- 9 years agoHelpfull: Yes(18) No(0)
- ans: 33 values of x
explanation: x must be 1 to 99
if x=1 not divisible by 6
if x=2 divisible by 6
in this way we get that if x=2,4,8,10,14,16,20,22,.....then z divisible by 6
so here we get two series
2,8,16,20.......98(total 17 values) and
4,10,16,22......94(total 16 values)
so,total 33 values of x.
- 9 years agoHelpfull: Yes(15) No(6)
- 68 values
(100-x)(100+x) - 9 years agoHelpfull: Yes(2) No(1)
- Yes,
Correct answer is 66.
I have marked 66 and it is correct as i got marks for this. - 9 years agoHelpfull: Yes(1) No(2)
- z=100pow2-xpow2
let x=2
then
z=10000-4
z=9996 which is divisible by 6
so the value of x=2
satisfied
- 9 years agoHelpfull: Yes(1) No(3)
- z=100^2-x^2
let x=2
z=10000-2^2
z=10000-4
z=9996
which is divisible by 6 - 9 years agoHelpfull: Yes(1) No(2)
- x value when used as 2 then z is divisible by 6
ie. z=10000-4
z=9996/6
z=1666
thus x=2 - 9 years agoHelpfull: Yes(0) No(4)
- Answer is 3
For values x= 2, 4 and 8 z value would be 96 84 and 36...which would be divisible by 6... - 9 years agoHelpfull: Yes(0) No(0)
- @anupam the pattern of the series is not clear..please explain in detail??
- 9 years agoHelpfull: Yes(0) No(0)
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