Elitmus
Exam
Numerical Ability
Log and Antilog
f(x)=log(base a) X+log(base b)X,given 1
Read Solution (Total 8)
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- If Given that X=1
then answer is 0.
F(1)=log1=log1=0 [No matter whats the base of Log if its, LOG1(base)100 then also the answer will be 0] - 9 years agoHelpfull: Yes(1) No(1)
- this is not proper question
question was
f(x)=log(base a) X+log(base b)X where 1 - 9 years agoHelpfull: Yes(1) No(1)
- What was the question :D
- 7 years agoHelpfull: Yes(1) No(1)
- The answer should be zero
- 9 years agoHelpfull: Yes(0) No(3)
- why the answer will be zero ?
- 9 years agoHelpfull: Yes(0) No(2)
- here condition is 1
- 9 years agoHelpfull: Yes(0) No(1)
- The question is let f(X)= log(base a)X +log(base b)X,
given 1 - 9 years agoHelpfull: Yes(0) No(1)
- Q was f(x)=log(base a) X+log(base b)X and 1
- 9 years agoHelpfull: Yes(0) No(1)
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