Q)f(x)=log(base a)x + log(base b)x;where a is greater than 1 and less than b and value of log(base a)x>1,then what is the minimum value of f(x)
optn:-0,1,2,1+log(not remember proper option)

• the last option was 1+log2(base3)..ans this ll be the ans..bcoz it can't be 1 and 1+log2(base3)
• 9 years agoHelpfull: Yes(8) No(0)
• my ans came as 2 .
• 9 years agoHelpfull: Yes(1) No(7)
• 1
  log(base a)x >1
  x > 1^a
  min value f(x) = f(0) = 1^0=1
• 9 years agoHelpfull: Yes(1) No(3)
• f(x)=logaX+logbX
  =logaX+logaX/logab(base a and argmnt b)
  =logax*(1+1/logab)
  =logax*((logab+logaa)/logab)
  =logax*(loga(b(a-1))
  acc to qusn logax >1
  so (1+)*(always greter then 1(loga(b(a-1)))
  so minimum value will be 1
  
• 9 years agoHelpfull: Yes(1) No(2)
• given 1
• 9 years agoHelpfull: Yes(0) No(0)
• 2 is the ans
• 9 years agoHelpfull: Yes(0) No(0)
• 0
  differentiate
  
• 9 years agoHelpfull: Yes(0) No(1)
• Ans is 2.
• 7 years agoHelpfull: Yes(0) No(0)