The sum of three from the four numbers A,B,C,D are 4024,4087,4524,and 4573.What is the largest of the numbers A,B,C,D.
a) 1650 b) 1164 c)1712 d) 1211

• 3(A+B+C+D)=4024+4087+4524+4573
  3(A+B+C+D)=17208
  A+B+C+D=5736
  We subtract the smallest number from the sum= largest number
  5736-4024=1712
• 8 years agoHelpfull: Yes(37) No(0)
• 3(a+b+c+d)=4024+4087+4524+4573
  by solving this we get
  a=1649
  b=1712
  c=1212
  d=1163
• 8 years agoHelpfull: Yes(3) No(1)
• 3(A+B+C+D)=4024+4087+4524+4573
  3(A+B+C+D)=17208
  A+B+C+D=5736
  sub the smallest no from the sum= largest no
  5736-4024=1712
  
• 8 years agoHelpfull: Yes(2) No(0)
• Equations are A+B+C=4024
  A+B+D=4087
  A+C+D=4524
  B+C+D=4573
  sOLVING LAST 2 EQUATIONS WE GET B=A+49
  USING IT IN 2ND EQ WE GET 2A+D=4038..(i)
  SUBTRACTING LAST EQUATION FROM 1ST EQ WE GET A-D=-549..(ii)
  SOLVING (i) ND (ii) WE GET A=1163
  USING A WE GET D=1712. SO 1712 IS THE ANS
• 8 years agoHelpfull: Yes(1) No(1)