In a clock Conventional clock with numbers 1 to 12 in order is cut into 3 pieces such that the

Sum of the 12 numbers=1+2+3+......+12=12*13/2=78
So we have to divide it into 3 slots such that the sum is 78 and sum of each slot is in AP, thus the 3 slots are 25,26,27. So the numbers can be:
3+4+5+6+7=25
8+9+10=27
11+12+1+2=26
8 years agoHelpfull: Yes(13) No(0)

In a clock there are total of 78 hrs..by dividing it by 3 we get 26..i.e., 26,26,26
with Arithmetic Progression(AP) difference of 1 means have to divide that as 25,26,27

Three parts are
1st part : 10,9,8
2nd part : 11,12,1,2
3rd part : 3,4,5,6,7

so that we can get the sum values of pieces at AP with the common difference of 1.
Hence total hours in the bigger part is 25 hrs
8 years agoHelpfull: Yes(5) No(0)
Sum of the 12 numbers=1+2+3+......+12=12*13/2=78
So we have to divide it into 3 slots such that the sum is 78 and sum of each slot is in AP, thus the 3 slots are 25,26,27. So the numbers can be:
3+4+5+6+7=25
8+9+10=27
11+12+1+2=26
8 years agoHelpfull: Yes(1) No(1)
first..remind that there is no saying that cut should be equal...so divide the clock into 3 pieces ...following this way..(3+4+5+6+7),(11+12+1+2),(8+9+10)...u will find that these sum are in A.P...& the common diff. is 1
8 years agoHelpfull: Yes(1) No(1)
1 2 3 4 5 6 7 8 9 10 11 12
sum of frst n natural num of the series of each piece is
10 , 32, 78
8 years agoHelpfull: Yes(0) No(5)
first piece 12,7,6,
second -11,8,5,2
third-10,9,4,3,1
8 years agoHelpfull: Yes(0) No(0)
cp of 1m= 40000/400 = 100rs
sp of 1m = 200/(3/2) = 400/3 rs
%gain = sp-cp / cp= ((400/3)- 100)/100 X 100 = 100/3 X 100 = 33.33%
7 years agoHelpfull: Yes(0) No(2)
12+13=25 but it is also correct na
7 years agoHelpfull: Yes(0) No(0)

In a clock (Conventional clock with numbers 1 to 12 in order)is cut into 3 pieces such that the sum of each piece in AP with a common difference of 1. What is the count of numbers in each piece? and what are the numbers?