Elitmus
Exam
Numerical Ability
Data Sufficiency
How many liters of 20% alcohol should be mixed with 60 % alcohol to get 32% alcohol
(1) We get 70 liters of 32% alcohol
(2) We used 21 lit of 60% alcohol, to prepare 32%
A if the question can be answered by using one of the statements alone, but cannot be answered by using the other statements alone
B if the question can be answered by using either statement alone
C if the question can be answered by using both statements together,but cannot be answered by using either statement alone
D if the question cannot be answered even by using both the statements together
Read Solution (Total 4)
-
- (B)
20 60
32
28 12
so the mixture will be in 28:12 ratio => 7:3 ratio
(1) if we have 70 liters of 32% alcohol that means we have 70*(7/(7+3)) liter = 49 liter of 20% alcohol
(2) if we have 21 liter of 60% alcohol that means 3x = 21(from the ratio)
=> x = 7
so we have 7 * 7(from ratio) liter of 20% of alcohol
so both statement alone is sufficient
that means Ans. B is correct - 9 years agoHelpfull: Yes(28) No(2)
- (B)
20 60
32
28 12
so the mixture will be in 28:12 ratio => 7:3 ratio
(1) if we have 70 liters of 32% alcohol that means we have 70*(7/(7+3)) liter = 49 liter of 20% alcohol
(2) if we have 21 liter of 60% alcohol that means 3x = 21(from the ratio)
=> x = 7
so we have 7 * 7(from ratio) liter of 32% of alcohol
so both statement alone is sufficient
that means Ans. B is correct
- 9 years agoHelpfull: Yes(5) No(1)
- option c..
the equation formed will be
0.2x+ 0.6y = .32z
where x is amout of 20% sol
y is amount of 60% sol
and z is amount of 32% sol
we can only find x by putting both the values of y and z from both the statements... - 9 years agoHelpfull: Yes(1) No(4)
- From statement 1 : The final output is 70 ltr 32% alcohal
so the final alcohal content is : 70 x .32 ltr = 22.4 ltr
From statement 2: 21 litre 60% alcohal was used.
so the initial alcohal content was: 21 x .6 = 12.6
The rest alcohal (22.4 - 12.6) = 9.8 ltr comes from 20% content.
The 20% content alcohal volume should be from (70 - 21) = 49 ltr
so its 20% alcohal will be .2 x 49 = 9.8 ltr hence satisfied
So both the statement are sufficient . [C] - 7 years agoHelpfull: Yes(0) No(0)
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