in a college basketball, a player awarded a "one-and-one" gets to shoot one free throw and , if successfull ,shoot a second one.each successfull free throw is worth one point.suppose a player succeeds at free throws 80% of the time.on average , how many points should this player expext to score foe each one-and-one?

• Let number of throws he take = 100.
  So, he will get success 80 times.
  for these 80 success he will get 80 chances more to throw according to one-and one, so 80% of these 80 will be 64.
  so total points he will score in 100 one-and one = 80+64 = 144.
  
  so the avg. =144/100.
  
  so answer = 1.44.
• 7 years agoHelpfull: Yes(1) No(1)
• Guys please submit the answer with proper explaination .Its very urgent & imp
• 8 years agoHelpfull: Yes(0) No(0)
• 0.8+0.8*0.8= 1.44
• 5 years agoHelpfull: Yes(0) No(0)
• Succeeds 1st time and fails 2nd time: 1*0.8*0.2 = 0.16
  Succeeds both time: 2* 0.8*0.8 = 1.28
  0.16+1.28 = 1.44
• 4 years agoHelpfull: Yes(0) No(0)