A man whose bowling average is 12.4, takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number of wickets taken by him before his last match is?
Solution

• The Flash!
  let x be runs (from previous matches) and n be wickets:
  bowling average=(number of runs given)/(wicket taken).
  :: x/n=12.4;
  now after 26 runs and 5 more wickets,
  :: (x+26)/(n+5)=12(decreased by 0.4)
  Solve to GET 85 wickets(i.e n)
• 8 years agoHelpfull: Yes(5) No(1)
• 12.4x+26/(5+x)=12
  12.4x+26=60+12x
  x=34/0.4=85
  
• 8 years agoHelpfull: Yes(1) No(0)