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A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21 .
What is the remainder left, when twice the number is divided by 3D?
a) 13
b) cannot be determined
c) 3
d) 42 (solution:c)

Read Solution (Total 3)

answer is el3
by using dividend= divisor×quotient+remainder
eqn 1 is D×q1+8=N
eqn2 is 3D×q2+21=N
eqn1×3-eqn2 gives
3D×q+3=2N
so remainder is 3
8 years agoHelpfull: Yes(13) No(0)

answer is 42.
8 years agoHelpfull: Yes(0) No(3)
supposingly N is the number, Q being the quotient

N=D x Q+8--------------------------------eqn1
N=3D x Q+21

twice the number..
2N=3D x 2Q+ 2 x 21

hence 42 is the remainder
8 years agoHelpfull: Yes(0) No(3)

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a) 8
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