There are 5 distinct integers a, b, c, d, e in ascending order.
(68-a)(68-b)(68-c)(68-d)(68-e) = 725.
What is a + b + c + d?

• 725 = 5*5*29
  
  It can also be written as 5*(-5)*(29)*(1)*(-1)
  
  a,b,c,d and e are distinct integers and also in ascending order.
  Therefore, a=(68-29)=39; b=(68-5)=63; c=(68-1)=67; d=(68-
  (-1)) = 69; e = (68-(-5))=73
  Hence, a+b+c+d = (39+63+67+69)= 238
  
  
• 8 years agoHelpfull: Yes(1) No(0)
• 725=5*5*29.
  so,a=63,b=63,c=39,d=1,e=1.
  so a+b+c+d+e=63+63+39+67+67=299
• 9 years agoHelpfull: Yes(0) No(4)