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What is the value of (2^2 + 4^2 + 6^2 + ... + 20^2 )?
A) 542 B) 756 C) 1540 D) 968
Read Solution (Total 4)
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- 1540
2^2[1+2^2+3^2+.....+10^2]= 4*10*11*21/6=1540 - 8 years agoHelpfull: Yes(3) No(0)
- 4+16+36+.........+400=4(1+4+9+...+10)
=1540 - 8 years agoHelpfull: Yes(1) No(0)
- 2^2(1^2+2^2+....+10^2)=1540
- 8 years agoHelpfull: Yes(0) No(0)
- ans is 1540
- 8 years agoHelpfull: Yes(0) No(0)
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