MBA Exam

Ten years ago,a family comprised four members whose average age was 4 years.Subsequently,two children were born and the average age of the family is the same today as it was ten years ago.What are the present ages of the two children,assuming that the difference in their ages is two years?

1) 10yrs,8yrs
2) 8yrs,6yrs
3) 5yrs,3yrs
4) 3yrs,1yr

Read Solution (Total 0)

MBA Other Question

In the given figure ABCD is a rectangle. P is any point
inside the rectangle. Prove that
PA2 + PC2 = PB2 + PD2.
This property is used to solve many problems . the numbers written beside PA,PB,PC,PD denote squares

a man sold a certain no of toyz all at a certain price.the no of toys that he sold isa three digit no and tens digit and unit digit is same and non zero,and the price of each toy is a two digit no. by mistake he reversed the digits of both,the no of items sold and the price of each of them. in doing so,he found that his stock account at the end showed 792 items more than it actually was.a.what could be the actual no of toys sold?b.if the faulty calculation show a total sale of rs5117,what is actual SP of each toy?pls also tell the method

1) 911,34
2) 119,37
3) 991,34
4) 991,43