A gives B as many as rupees B has and C as many as rupees C has.Similarly B gives A as many as rupees A has and C as many as rupees C has, C similarly gives B as many as rupees B has and A as many as rupees A has..Now finally each of them has 32 rupees.how much rupees does A has initially?

a) 52 b)56 c)60 d)62

• From the reverse engineering process
  32 32 32
  16 16 64(C given to A and B what they have)
  08 56 32(B given to A and C what they have)
  52 28 16 (A given to B and C what they have)..
• 9 years agoHelpfull: Yes(9) No(0)
• initially
  A
  B
  C
  after A gives
  A has ->A-B-C
  B has ->2B
  C has ->2C
  after B gives
  A has ->2A-2B-2C
  B has ->-A+3B-C
  C has ->4C
  AFTER C gives
  A has ->4A-4B-4C=32---------1
  B has ->-2A+6B-2C=32----------2
  C has ->-A-B-7C=32-----------3
  ON solving 1,2,3 A=52
• 9 years agoHelpfull: Yes(8) No(0)
• 52 do it in reverse form
• 9 years agoHelpfull: Yes(2) No(0)
• do this using back tracking
  at the end
  A B C
  32 32 32
  half each of A and B was given to them by C
  so
  A B C
  16 16 (32+16+16=48)
  now
  half of A and C money was given to them by B
  A B C
  8 (16+8+32=56) 32
  now half money of B and C was given to them by A
  therefore
  A B C
  (8+28+16=52) 28 16
• 9 years agoHelpfull: Yes(1) No(1)
• 52 ,if b and c has 10 rupees each
• 9 years agoHelpfull: Yes(0) No(0)