) In an examination involving quantitative aptitude and logical reasoning, 65% examinees cleared quantitative aptitude test while 70% cleared logical reasoning test. If 50% examinees passed both the tests, then how many failed in both tests?
a)35% b)15% c)30% d)20%

• total number of students who passed in atleast one exam=65+70-50=85
  students who failed in both=100-85=15%
  answer:(c)
• 9 years agoHelpfull: Yes(17) No(2)
• let total student =100
  QA =65
  LR=70
  QA+LR=50
  ::only QA=65-15==15
  ::only LR = 70-50=20
  ::both QA+LR=====50
  
  total passing students 50+15+20=85
  remaining failed students = 100-85=15%
  
  use venn diagrams for better understandings ;)
• 9 years agoHelpfull: Yes(9) No(1)
• First consider there are 100 students
  A - QUANT 65
  B- LOGICAL 70
  A+B = 50
  ONLY A= 65- 50 = 15
  ONLY B = 70-50
  SO TOTAL PASSED STUDENTS A AND B = 15+20=35
  BOTH A AND B =50 SO 50-35 =15
• 9 years agoHelpfull: Yes(3) No(0)
• ans:b
  p(AUB)=p(A)+p(B)-p(AnB)
  =65+70-50
  =85%(the persons who cleard all)
  the persons who did not clear any=100-85=15%
• 9 years agoHelpfull: Yes(1) No(0)
• A+R=100%(TOTAL APPERED)
  65%=PASSED QUAN
  70%=REASONING
  35%FAILED QUANT
  30%=FAILED REASONING
  TOTAL FAILED PASSED IN BOTH=50%
  TOTA FAILED IN BOTH=50-(35+30)=15%
• 6 years agoHelpfull: Yes(1) No(0)
• option B is correct as ....
  20% (70-50) would be passed only in reasoning and likely 15%(65-50) would be passed into quantitative.....so 20+50+15 passed in both the test....so 100-(20+50+15) gives us 15
• 9 years agoHelpfull: Yes(0) No(0)
• 35%+30%+50%-100%=15%
• 8 years agoHelpfull: Yes(0) No(0)
• answer is b) 15%
  solution is:-
  passed% + failed%=100%
  (65+70-50)% + failed%=100%
  85% + failed%=100%
  gives, failed %=15%
• 7 years agoHelpfull: Yes(0) No(0)
• let, total no of student =100
  then 65 cleared QA & 70 cleared LR
  And 50 no. of students cleared both.
  so no. of student who only cleared QA are (65-50)=15 and LR=(70-50)=20
  so,no of failed students=100-(15+20+50)=15
• 2 years agoHelpfull: Yes(0) No(0)