A bus covers a certain distance at a speed of 54 kmph excluding stoppages and 45 kmph including stoppages.for how many minutes does the bus stop per hour?

• Due to stoppages, it covers 9 km less.
  
  Time taken to cover 9 km = 9/54 x 60 min = 10 min.
  
  
• 8 years agoHelpfull: Yes(12) No(0)
• Due to stoppages,it covers (54-45) 9 km less.
  time taken by bus stop per hour=9/54*60=10 min
• 8 years agoHelpfull: Yes(3) No(0)
• In an hour without stoppage, total distance traveled = 54 km.
  Time to cover 54 km distance including stoppage= 54/45x60 minute=72 minutes.
  
  Since , in 72 minutes of traveling bus stoppage time is 72-60=12 minute
  Hence in one minute, bus stoppage time = 12/72 minute.
  Hence in an hour(60 min.), bus stoppage time= 12/72x60=10 min.
• 8 years agoHelpfull: Yes(2) No(0)
• The distance covered in both the cases is 'd'. Whereas the time differs in the second case due to the stoppage.
  
  We know,
  d=s*t
  
  case 1 : d=54*t
  case 2 : d=45*(t+s) , where 's' is the total stoppage time
  
  equating both, we get the ratio t:s=5:1, ie., s/t=1/5=.2 =20% of total time.
  
  Hence for an hour it would be 12 min
  
• 8 years agoHelpfull: Yes(1) No(3)
• due to stopage u2 cover less distance that is (54-45=9)km, so total min where the bus stop per hr is 9/54*60=10 min
• 8 years agoHelpfull: Yes(1) No(0)
• 10MIN
  since ratio of speed is inversely proportional to time
  
  
  
  
• 8 years agoHelpfull: Yes(0) No(0)
• In 1hr it covers 54 km without stoppage .
  Distance = 54km and speed. -54km/hr
  So in 60 minutes it covers 54km
  And the same distance is covered at speed 45km/hr stoppage. So time= distance/ speed , time =54/45 = 1.2 means 80min .
  So every hours it stopps for 20 minute.
  
• 8 years agoHelpfull: Yes(0) No(2)
• Difference between the speeds=54-45=9
  =9/54*60
  =10
• 7 years agoHelpfull: Yes(0) No(0)
• The distance covered in both the cases is 'd'. Whereas the time differs in the second case due to the stoppage.
  
  We know,
  d=s*t
  
  case 1 : d=54*t
  case 2 : d=45*(t+s) , where 's' is the total stoppage time
  
  equating both, we get the ratio t:s=5:1
  stopping time=1/(5+1)*60=10 min Answer
• 7 years agoHelpfull: Yes(0) No(0)