Two identical circles intersect so that their centres, and the point at which they intersect, from a square of side 1 cm. The area in sq. cm of the portion that is common to the two circles is

• we will get two sectors when we join circle centres and intersection points .
  By subtracting area of two sectors from area of square we will get common area.
  area of square 1 cm^2
  area of sector =pi*R^2*(angle)/360
  Here angle=90 degree
  angle can be found out by drawing diagonals on square and applying sin.
  here area of 2 sectors= 2*pi*1^2*90/360=pi/2
  answer is pi/2-1
• 8 years agoHelpfull: Yes(5) No(0)
• area of two quarter circles=2.pi/4
  are of two triangles= 2*1/2
  area between two circles in common=pi/2-1
• 8 years agoHelpfull: Yes(1) No(0)