a,b,c are non negative integers such that 28a+30b+31c=365. a+b+c=?

• consider it as a year such as
  feb =28days----------->1
  April,june,september,november=30 days---->4
  january,march,may,july,august,october december=31 days------->7
  so 1+4+7=12
  
• 9 years agoHelpfull: Yes(3) No(0)
• put a=1; b=4; c=7
  28*1+30*4+31*7=365
  so; a+b+c=12
  please see 28, 30 and 31 are the days in months.
• 9 years agoHelpfull: Yes(1) No(0)
• 7+4+1=12
  7month=31day
  4month=30day
  1month=28
• 9 years agoHelpfull: Yes(0) No(0)
• 12. no. of days in a year=365
  28- feb
  30- apr, jun, sept, nov
  31- jan, mar, may, jul, aug, oct, dec
• 9 years agoHelpfull: Yes(0) No(0)
• 28a+30b+31c=365. So 28,30,31st is nothing but the number of months having 28,30,31st days.
  As we know in 365 days, one 28days month 8 of 31st day month and 4 of 30day months.
  28*1+30*4+31*8=365.
  => a+b+c= 1+4+8=12 .
• 9 years agoHelpfull: Yes(0) No(0)