two vehicles A and B leave from Y to x . A overtake B at 10.30 am and reaches city X at 12.00 pm .it wait for 2 hour and return to city Y.on its way it meet B at 3;00 pm and reaches city X . waits for 1 hour and return to city Y .After how many hour will B reaches city Y from the time A overtook him for the first time?
a} 50 hour
b] 41.5 hour
c]49.5 hour
d]37.5 hour

• Explanation:
  
  Let us understand the diagram. Vehicle A overtaken B at 10.30 am and reached X at 12 pm. It started at 2 pm and met B at 3 pm at Q. It means, Vehicle A took one hour to cover distance 'n', So it should be at Q at 11 pm. It is clear that Vehicle A takes 0.5 hour to cover distance 'm'. Now vehicle B travelled from 10.30 am to 3 pm to meet A. So it took 4.5 hours to cover m. So Speeds ratio = 4.5 : 0.5 = 9 : 1.
  Now Vehicle A took a total of 1.5 + 3 = 4.5 hours to travel fro P to Y. So It must take 4.5 × 9 + 1 = 41.5 hours
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