TCS
Company
Numerical Ability
Geometry
A semicircle is drawn with AB as its diameter. From C, a point on AB, a line perpendicular to
AB is drawn, meeting the circumference of the semicircle at D. Given that AC = 2 cm and CD
= 6 cm, the area of the semicircle (in sq. cm) will be:
a) 50π
b) 55π
c) 31π
d) 82π
Read Solution (Total 3)
-
- By using right triangles adc,bdc,adb solve by Pythagorean theorem.first find ad^2from triangle adc=40.substitute that in triangle bcd means ad^2+bd^2=[ac+bc]^2.for to find bd use triangle bcd.u will get an exp in terms of bc^2.by using that substitute in ac+bc. ^2 ans is 50 pie
- 8 years agoHelpfull: Yes(2) No(0)
- answer is 50pi
draw the diagram you'll get a triangle and from this you'll get radius of semicircle
apply the area's formula then - 8 years agoHelpfull: Yes(1) No(1)
- suppose e be the centre
then ce= radius- 2
cd=6
(radius)^2 =6^2 + (radius -2)^2
radius = 10
area of semicircle =pi(radius)^2/ 2 = pi * (100)/2 =50pi - 8 years agoHelpfull: Yes(1) No(1)
TCS Other Question