TCS
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Numerical Ability
Arithmetic
26. In this question, A^B refers to A raised to the power B.
Assume that the rate of consumption of coal by a locomotive engine varies as the square of its speed and is 1000 kg per hour when the speed is 60 km per hour, when in motion. If coal costs the railway company Rs. 15 per 100kg and if the other expenses of running the train is Rs. 12 per hour, find a formula for the cost in paise per kilometre when the speed is per hour.
o (1200/S)+(25S/6)
o (1200/S)+(25S^2/6)
o (1200/S)+(5S^2/18)
o None of these
Read Solution (Total 1)
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- 1000=k 60^2
k=5/18
total cost =coal cost + other cost
=12*(100/s)+5/18s^2(s*15)
c= 1200/s+(s25/6) - 9 years agoHelpfull: Yes(5) No(1)
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