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Numerical Ability
Number System
number of three multiples of 1800
Read Solution (Total 9)
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- 2^3*3^2*5^2 no. of three multiples are 7
- 9 years agoHelpfull: Yes(5) No(2)
- 36
1800= 2^3*3^2*5^2;no of factors=(3+1)(2+1)(2+1)
- 9 years agoHelpfull: Yes(2) No(0)
- Its answer is 36 because No of factors = (p+1)(q+1)(r+1)
(3+1)(2+1)(2+1) = 36 - 9 years agoHelpfull: Yes(1) No(0)
- 1800/9=200
no of 3 =2 - 9 years agoHelpfull: Yes(1) No(0)
- 1800/3=600
- 9 years agoHelpfull: Yes(0) No(2)
- 22, the answer is obtained by examining the multiples of 600 because 1800/3=600
- 9 years agoHelpfull: Yes(0) No(2)
- 3*600
- 9 years agoHelpfull: Yes(0) No(0)
- 3*600
- 9 years agoHelpfull: Yes(0) No(0)
- no of thee multiple of 1800=3^2*2^2*5 is 20
- 9 years agoHelpfull: Yes(0) No(0)
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