A tiger is 50 leaps of its own behind adden the tiger takes 5 leaps per minute to the deers 4 .If the tiger and the deer cover 8 meters and 5 meter per leap respectively.What a distance in meter will the tiger have to run before it catches the deer

• 800 meters
• 8 years agoHelpfull: Yes(0) No(0)
• ans: 800 m
  let , after starting deer travel 'x' distance and then catches by tiger
  so,equation:
  (50*8 + x) / (8*5) = x / (5*4)
  x=400
  therefore, total dist. travel by tiger to catch the deer =400 + x = 800
• 8 years agoHelpfull: Yes(0) No(0)