In a market 4 men are standing. The average age of the four before 4years is 45, after some days one man
is added and his age is 49. What is the average age of all?
a) 43 b)45 c)47 d)49

• avg 4 years before-45*4=180
  avg now=180+4*4=196
  avg of all=(196+49)/5=245/5=49
  ANS=d.
• 9 years agoHelpfull: Yes(5) No(0)
• d) 49
  
  Present total age of 4 men=(4*45)+(4*4)=196
  So present average of all 5 (including new man) = (196+49)/5=49
• 9 years agoHelpfull: Yes(1) No(1)
• avg age of 4 persons before 4 years =45+4=49
  a+b+c+d=49*4=196;
  avg of all=196+49/5=49
• 9 years agoHelpfull: Yes(1) No(0)
• sum of present age of 4 men=(45*4)+(4+4+4+4)=196
  one ,an is added up so 196+49=245
  avg=245/5=49
• 9 years agoHelpfull: Yes(1) No(0)
• Let avg be x
  Avg age of 4 before 4 yrs is = (x/4)-4
  Given
  (X/4)-4=45
  By solving x=196
  Given one person is added with age 49
  That is (x+49)/5
  X=196 (substitute in above eq)
  Then ans is (196+49)/5=49
• 7 years agoHelpfull: Yes(1) No(0)
• avg 4 yrs before-45*4=180
  now-180+4*4=196
  now one man added his age is 49 then new avg is
  (196+49)/5=49
• 9 years agoHelpfull: Yes(0) No(0)
• avg 4 yrs before-45*4=180
  now-180+4*4=196
  now one man added his age is 49 then new avg is
  (196+49)/5=49
  
• 9 years agoHelpfull: Yes(0) No(0)