Kavya and madhav leaves point x and y towards y and x respectively simultaneously and travel in the same route.After meeting each other on the way,kavya takes 4 hours to reach her destination ,while madhav takes 9 hours to reach his destination.If the speed of kavya is 48 km/hr ,what is the speed of madhav?
a) 72 kmph b)32 mph c)20mph d)non

• Ans is 32Kmph
  Sol 1)
  As per ratio proportion theorem, t/4=9/t implies this t^2=36, t=6
  where t is the time taken by them to meet each other.
  and s is speed of madhav.
  kavya-> t 4
  ___x_______|_d-x_______ total=d(distance)
  9 | t t 4
  ___x_______|_d-x_______ total=d(distance)
  9 | t
• 9 years agoHelpfull: Yes(1) No(0)
• Sol 1)
  As per ratio proportion theorem, t/4=9/t implies this t^2=36, t=6
  where t is the time taken by them to meet each other.
  and s is speed of madhav.
  kavya->
  t 4
  ___x_______|_d-x_______ total=d(distance)
  9 | t
• 9 years agoHelpfull: Yes(0) No(0)
• and now to cover x km,
  kavya takes t hrs and madhav takes 9hrs
  therefore, 48t=9s
  48x6=9s
  s=32kmph,
  
  Sorry I post full solution in last post, but dont know how it get short.
• 9 years agoHelpfull: Yes(0) No(0)
• If you dont understand the solution then just ping me, I gave you full solution :)
• 9 years agoHelpfull: Yes(0) No(1)