Roy is now 4 years older than Erik and half of that amount older than Iris. If in 2 years, roy will be twice as old as Erik, then in 2 years what would be Roy's age multiplied by Iris's age?

• Are yaar half of wat amount? Adha question likhte ho, hum jaise adha dimag wale insan thodi samjhnge. Thod thik se question likho plz.
• 9 years agoHelpfull: Yes(6) No(1)
• let erik's age be x
  then roy is x+4
  
  iris age be y
  then roy is y+y/2
  
  after 2 years
  erik is x+2
  roy is x+4+2 (x+6)
  
  then x+6 = 2(x+2)
  x=2 (erik)
  x+2=4 (roy)
  y+y/2=4 then y=4(iris)
  after 2 years roy is 8 years old and iris is 6 years old 6*8=48
  
• 9 years agoHelpfull: Yes(5) No(2)
• R=E+4
  R=I+2
  In 2 years,
  R+2=2(E+2)
  i.e. R+2=2E+4
  i.e. E+4+2=2E+4
  i.e. E=2
  Also I+4=2E+4
  i.e. I+4=8
  i.e I=4
  after 2 years,product of ages=(R+2)*(I+2)=8*6=48
  
• 9 years agoHelpfull: Yes(4) No(0)
• Let ages of Roy, Iris and Eric be R, I and E.
  
  Since Roy is now 4 years older than Erik
  
  Hence R = 4 + E -----------[1]
  
  Also we have R = 2 + I --------------[2]
  
  If in 2 years, Roy will be twice as old as Erik, then in 2 years
  
  ⇒ R + 2 = 2(E + 2)
  
  ⇒ R + 2 = 2E + 4
  
  ⇒ R = 2E + 2 ----------- [3]
  
  Since the LHS of eqns 1 and 3 are same,
  
  Hence we compare their RHS
  
  ⇒ 4 + E = 2E + 2
  
  ⇒ 2E – E = 4 – 2
  
  ⇒ E = 2
  
  Putting this value of E in eqn 1, we have
  
  ⇒R = E + 4 = 2 + 4 = 6
  
  Putting this value of R in eqn [2],
  
  We have R = 2 + I
  
  ⇒ I = R – 2 = 6 – 2 = 4
  
  Hence, after 2 years, age of Roy will be 8 years and age of Iris will be 6 years
  
  Hence,
  
  The product of their ages is 8 × 6 = 48
• 6 years agoHelpfull: Yes(1) No(0)