a motorcyclist left point A for point B .two hours later another motorcyclist left A for B and arrived at B at the same time as the first motor cyclist .had both the cyclist started simultaneously from A and B travelling towards each other ,they would have met in80 minutes.how much they time did it take the faster motorcyclist to tarvel from A to B

• let the dist b2n A and B be 'd' km
  d=at=b(t-2)
  b=at/(t-2)
  80/40(a+b)=d=at
  4/3(a+b)=at
  4/3{a+at/(t-2)}=at
  on solving, t=4 hrs
  (t-2)=2 hrs
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