Campus Maths Puzzle Numerical Ability Number System

What is the greatest power of 143 which can divide 125! exactly???

Read Solution (Total 4)

143 = 11 × 13. So highest power of 13 should be considered in 125!. [125/13]=9
8 years agoHelpfull: Yes(9) No(5)

CAN U PLS EXPLAIN IT CLEARLY
8 years agoHelpfull: Yes(2) No(1)
Explanation:
143 = 11 × 13. So highest power of 13 should be considered in 125!.

Highest power of 11 in 125! is 12 but highest power of 13 is only 9. That means, 125!=1112×139×....1112×139×....
So only nine 13's are available. So we can form only nine 143's in 125!. So maximum power of 143 is 9.
8 years agoHelpfull: Yes(2) No(1)
to know how many 0 we hve to find number of 2s and 5S by factorization, by factorizing a number it has many n of 2s but only by knowing number of 5s we can tell how many zeros are there

in the same way this ques has many 11*13 =143
to calculate how many 143s are present simply calculate 13 s
it has 9 13s
4 years agoHelpfull: Yes(0) No(0)

Campus Other Question

(2^48)! has 12^n.what is n? Platinum is sold in bars of weights ranging from 17 grams to 1760 grams in 7 gram increments. Each bar is sealed in an opaque box weighing 47 grams . The box used for packaging has no marks on it indicating the weight of the bar inside.
The precious metals merchant selling the boxes has put the packed bars into shelves based on weight. However , to be certain , he weighs the packed box in an equal arms two pan balance, and a set of weights( which is common for all the bars and which he considers as “standard” weights.). Each of these weighs an integral number of grams, and have their weight marked on them. The merchant, a superstitious man, always places the packed box of platinum on the left pan, and places the appropriate weights in the left pan or the right pan or both until balance is achieved. This suffices hi m to tell the weight of the packed bar.
What is the minimum number of “standard” weights the merchant must have to be able to accurately determine the weight of all his packed boxes?