consider x=y=1
x=y
x^2=xy (multiplying both side by x)
x^2-y^2=xy-y^2 (subtracting y^2 from both side)
(x+y)(x-y)=y(x-y) { since x^y=(x+y)(x-y) }
x+y=y { x-y got cancelled }
i.e, 1+1=1
2=1 (but mathematically it is not correct)
find the twist?

• If we firstly assumed that x=y
  Then
  In second step x^2=xy instead of xy it should be either x^2 or y^2
• 9 years agoHelpfull: Yes(8) No(2)
• x-y =0
  so we can't divide by zero on both side
  ex if a=8, b=7,c=0
  then a*b=b*c=0
  so now divide with c on both side
  a=b but mathematically it is not correct
• 9 years agoHelpfull: Yes(3) No(2)
• line 5 where (x+y)(x-y)=y(x-y)
  while subsituting values it is
  (1+1)(1-1)=1(1-1)
  2*0=1*0
  so we cannot cancel 0 with 0..thus the trick lies in line 5.
• 9 years agoHelpfull: Yes(3) No(0)
• twist in this :-
  x^2-Y^2 is not equals to X^Y
  or (x+y)(x-y) is wrongly replaced with x^2-y^2
• 9 years agoHelpfull: Yes(1) No(7)
• since x=y=1
  in line 4 i.e x^2-y^2=xy-y^2 become zero
  
• 9 years agoHelpfull: Yes(0) No(0)
• the number is 2 because the number of 1's is two on left and the number of 1's in right is 1
• 8 years agoHelpfull: Yes(0) No(1)
• that is in the 5th step(x-y) got cancelld. here x=y was assumed.
  so x-y=0; hence it cant be cancelled as 0/0 is infinity.
• 8 years agoHelpfull: Yes(0) No(0)