The ratio of efficiency of A is to C is 5:3.The ratio of no.of days taken by B is to C is 2:3.A takes 6 days less than C,when A and C completes the work individually.B and C left the work after 2 days.the no of days taken by A to finish the remaining work?

a) 4.5
b) 5
c) 6
d)28/3

• EFFICIENCY OF A AND C = 5:3 (RATIO OF WORK DONE AND EFFICIENCY IS JUST REVERSE)
  RATIO OF WORK DONE = 3:5 (LET IT BE 3X : 5X)
  GIVEN :DIFFERENCE BETWEEN A'S AND C'S WORK DONE IS 6 DAYS SO, 5X-3X=6, X=3;
  SO, A DO WORK IN 3*3= 9 DAYS
  C DO WHOLE WORK IN=5*3=15 DAYS
  NOW RATIO OF WORK DONE OF B AND C IS 2:3 (LET IT BE 2X : 3X)
  AS WE HAVE CALCULATED C'S TOTAL WORK DONE IN 15 DAYS SO, 3X=15 DAYS , X=5
  THEN B'S TOTAL WORK DONE IS 2*5= 10 DAYS
  NOW WE HAVE TOTAL WORK DONE BY A ,B AND C IN 9,10 AND 15 DAYS RESPECTIVELY
  B ANC WORK FOR 2 DAYS MEANS (1/10 +1/15)*2=1/3
  REMAINING WORK=1-1/3 = 2/3
  A DO TOTAL WORK IN 9 DAYS SO, 2/3 WORK IS DONE IN (9*2/3)=6 DAYS
• 9 years agoHelpfull: Yes(47) No(0)
• 
  
  A : B : C
  Efficiency 10 : 9 : 6
  No of days 9x : 10x : 15x
  
  given=> 15x-9x = 6
  hence, x = 1
  Number of days taken by A = 9 and daily work done=10
  Number of days taken by B= 10 and daily work done=9 (total work =90)
  Number of days taken by C = 15 and daily work done=6
  
  work done by B and C in initial 2 days =30
  
  rest work =60
  
  Number of days required by A to finish = 60/10=6 days
• 9 years agoHelpfull: Yes(20) No(3)
• A : B : C
  Efficiency 10 : 9 : 6
  No of days 9x : 10x : 15x
  
  given=> 15x-9x = 6
  hence, x = 1
  Number of days taken by A = 9 and daily work done=10
  Number of days taken by B= 10 and daily work done=9 (total work =90)
  Number of days taken by C = 15 and daily work done=6
  
  work done by B and C in initial 2 days =30
  
  rest work =60
  
  Number of days required by A to finish = 60/10=6 days
  
• 9 years agoHelpfull: Yes(1) No(5)
• A : B : C
  Efficiency inline fn_jvn rightarrow 10 : 9 : 6
  No of days inline fn_jvn rightarrow 9x : 10x : 15x
  inline fn_jvn Rightarrow 15x-9x = 6
  inline fn_jvn therefore x = 1
  Number of days taken b A = 9
  Number of days taken by B= 10
  Number of days taken by C = 15
  work done by B and C in initial 2 days = inline fn_jvn frac{2times 1}{6} = inline fn_jvn frac{1}{3}
  rest work =inline fn_jvn frac{2}{3}
  Number of days required by A to finish inline fn_jvn frac{2}{3} work = inline fn_jvn frac{2/3}{1/9} = 6 days
• 9 years agoHelpfull: Yes(0) No(3)