1)The difference between two no is 9 and the product of the two is 14.What is the square of their sum?
a)120 b)130 c)137 d)145

• X-Y=9
  XY=14
  (X-Y)2=X2+Y2-2XY
  81=X2+Y2-28
  X2+Y2=109
  (X+Y)2=X2+Y2+2XY
  (X+Y)2=109+28=137
  
• 9 years agoHelpfull: Yes(13) No(0)
• we can solve bye (x+y)^2-(x-y)^2=4xy
• 9 years agoHelpfull: Yes(2) No(0)
• 137 is the ans
• 9 years agoHelpfull: Yes(0) No(0)
• a-9=9,ab=14
  (a-b)2=a2+b2-2ab here we use a-b and ab
  a2+b2=(a-b)2+2ab
  a2+b2=81+28=109
  (a+b)2=109+28=137(use a2+b2+2ab formula)
• 9 years agoHelpfull: Yes(0) No(0)
• 137 is ans
• 9 years agoHelpfull: Yes(0) No(1)
• 137
  solve by using (a+b)^2 formula
• 9 years agoHelpfull: Yes(0) No(0)
• Data Insufficient !!
  Like If You Agree !!
• 9 years agoHelpfull: Yes(0) No(4)
• (x-y)=9.
  X^2+y^2-2xy=81
  X^2+y^2=81+28=109.
  Then (x+y)^2= x^2+y^2+2xy=109+18=137
• 9 years agoHelpfull: Yes(0) No(0)
• 2(ab+bc+ca)+2(a+b+c)=766
  2(250-a-b+300-b-c+216-a-c)+2(a+b+c)=766
  1532-(a+b+c)=766
  2(a+b+c)=766
  a+b+c=383
• 6 years agoHelpfull: Yes(0) No(0)