Syntel
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Numerical Ability
Pipes and Cistern
One pipe fills in 4 hrs and another in 5hrs when they both work alternately
how much time will be taken to fill the tank.
Read Solution (Total 2)
-
- Unit work is done in 1/4hrand 1/5hr
So,in 4hr working alternatively total work is
(1/4)*2+(1/5)*2=9/10
Now work left is
1-(9/10)=1/10
This work is done by 1st pipe in
4/10 hr=24 min.
So total time taken is 4hr24min - 9 years agoHelpfull: Yes(4) No(1)
- work is alternate so work done in two hours = 1/4+1/5=9/20 : work done in two hours
in second two hours = 18/20
and remaining work is 2/20
so 1/4 will work for next alternate day
= remaining work/time required to complete work =2/20*4/1=0.4
that is o.4 of 1 hour = 24 minutes
so total time required is 4 hr. 24 min. - 8 years agoHelpfull: Yes(0) No(0)
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