if x+y+z=3 then what is then the integer which is nearest to the maximum value of x^2y^3z

• ans is 1
  in order to maximize the value of x^2y^3z^ z should be maximum
  lets take z=3;
  but for this x=y=0
  but 0^0 is not defined
  now take,
  x=0 and y=1
  z=2
  now 0^1=1
  1^2=1
  
  
  hence all possible combination will give ans as 1
  
• 9 years agoHelpfull: Yes(3) No(3)
• ans is 1
  take x=0 y=1 z=2
  0^1=1
  1^2=1
  
  then max value is 1
• 9 years agoHelpfull: Yes(1) No(1)