A person run from A to B He took of the time less to reach B when compare to run

time becomes 3/4 th time of the original.
speed will rise reciprocally and the final speed will be 4/3 times of the original.. i.e a 1/3 time increase or 33.33% increase.
8 years agoHelpfull: Yes(4) No(0)
let normal time=x
run time=x-0.25x=(3x/4)
normal speed u= d/x
running speed v=d/0.75x
v/u%=133.33
increament=33.33.......
8 years agoHelpfull: Yes(1) No(0)
for example if any body can go 400 km in 4 hours that means his speed will become 100 km/h.so this is normal speed of that man.if he take 1/4 of the time less taht means 3 hours for 400 km so
distance is equal then
v1xt1=v2xt2
100x4=v2x3
v2=400/3=133.33
that means his speed is increase 33.33 this is my answer.
8 years agoHelpfull: Yes(1) No(1)
ratio b/w time is: 1: 3/4
speed: 3/4: 1
therefore, ((3/4-1)/ 3/4) *100 =33.3 %
8 years agoHelpfull: Yes(1) No(0)
let T = normal time
old speed/new speed = T-(1/4)T/T
old speed/new speed = 3/4
new speed=(4/3)old speed
% increase = 33.3%
8 years agoHelpfull: Yes(0) No(0)
(v+(v*x/100))/v=100/75 => x=33.33%
8 years agoHelpfull: Yes(0) No(0)
decrease is 1/4 that is 1/x
so the increase will be 1/x-1 that is 1/4-1=1/3
(i.e)100/3=33.33
8 years agoHelpfull: Yes(0) No(0)
speed of a is 1/4 less than b
than 1/(4-1)=1/3
which is fraction so
1/3=33.3%
7 years agoHelpfull: Yes(0) No(0)

A person run from A to B.He took ¼ of the time less to reach B when compare to run at normal Speed.Then
how many percentage he has increased his speed?
a)40 b)44.4 c)33.3 d)22.2