The value of diamond varies directly as the square of its weight. If a diamond falls and breaks into two pieces with weights in the ratio 2:3. what is the loss percentage in the value?

• As the diamond varies its value in squere.. After when it has broken its value is,
  3^2+2^2=13.
  Before it has broken its value was
  (2+3)^2=5^2=25.
  Percentage loss is ((25-13)/25)*100=48%
• 9 years agoHelpfull: Yes(22) No(0)
• v=w^2
  ratio: 2:3
  total value:5
  2^2+3^2=5^2
  13=25
  loss=(diff/true value)*100
  =(12/25)*100
  =48%
• 9 years agoHelpfull: Yes(4) No(0)
• Ans :- 48%
  
  Solution:-
  
  Let the weight of diamond be 'W'
  V is proportional to W^2
  
  Now diamond breaks into weight ratio of 2:3
  That is 2x + 3x = W
  x= W/5
  
  2x = 2/5W
  3x = 3/5W
  
  The value of new diamond = 4/25 W^2 + 9/25 W^2
  = 13/25 W^2
  Loss percentage in value = (W^2 - 13/25W^2) * 100/W^2
  = (12/25) * 100
  = 12*4
  = 48%
  
• 9 years agoHelpfull: Yes(2) No(0)
• let weight be x
  then value will b proportional to x^2.
  after breaking te
  he weights are 2y and 3y =(2y+3y=5y)
  so value after braeking=5y^2=25y^2.
  cumulatively =2y^2+3y^2=13y^2
  therefore (loss=(25y^2-13y^2)/25y^2))*100)= 48%
• 9 years agoHelpfull: Yes(0) No(0)
• The answer is :48%
  
• 9 years agoHelpfull: Yes(0) No(0)
• As already given that diamond is broken intwo two pieces in ratio 2:3.
  so.let weight of big diamond be 5,then broken diamond will be 2 and 3 respectively.
  let value be x.
  then x=k*25 for bigger diamond.
  broken diamond be...y=k*4
  z=k*9
  so total price 13k..
  hence loss%=25k-13k/25k=12/25*100=48%
  
  
  
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• For eg let us assume the weight of diamond is 10g and its value is 10*10=100
  if diamond is broken and such that its weight is in the ratio 2:3 then 4:6 and its value is 4^2 + 6^2= 16+36 =52 so the loss percentage is 48%.
• 9 years agoHelpfull: Yes(0) No(0)
• 48%
  let value of diamond=x
  weight=y
  x=y^2
  after broken, weight of two pieces is 2/5(y),3/5(y)
  value of diamond is (4/25(y^2)+9/25(y^2))=13/25(y^2)
  y^2-(13/25(y^2))=12/25(y^2)
  loss=12/25=48%
• 8 years agoHelpfull: Yes(0) No(0)