how many positive integers less than 600 can be formed using 1,2,3 and 6 for its digit. with each digit behind used only once

• Three digit number: 3*3*2=18(since the number should be less then 600)
  Two digit number:4*3=16
  One digit number:4
  so 18+16+4=34(Ans)
• 8 years agoHelpfull: Yes(12) No(8)
• Num of possible 1 digit numbers = 4
  
  Num of possible 2 digit numbers = 4*3 = 12
  
  For 3 digit numbers, to meet the condition the number should be less than 600, so 6 cannot be in the hundredth position.
  Num of possible 3 digit numbers = 3*3*2 = 18
  
  Total +ve integers meeting the condition = 4+12+18 =34
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• 8 years agoHelpfull: Yes(8) No(0)
• For hundred place there are 3 choices i.e.,1,2 and 3.----3
  For tens place there are again 3 choices(excluding above digit used and including 6)---3
  and for unit place we have 2 digits left----2
  So, the answer will be---3*3*2=18.
  So, we have 18 positive integers less than 600 that can be formed using 1,2,3 and 6!
• 8 years agoHelpfull: Yes(1) No(5)
• 
  Coz the no. Should be smaller than 600 so 6 can't be kept on the first position..
  So the arrangement for 1,2 or 3 in the first place will be 3c2*2! Each...so in total its 18
• 8 years agoHelpfull: Yes(0) No(4)
• 34
  3 digit no. =18
  2 digit no.=12
  1 digit no. =4
  thus total =34 numbers
• 8 years agoHelpfull: Yes(0) No(0)
• The positive integer less than 500 can be formed using 1,2,3,6 are
  since for one digit we have 4
  for two digit we have 4*3
  for three digit we have 3*3*2 because the hundred th digit not be 6 so it has only 3 ways at first position
  so finally ,4+12+18=34
• 8 years agoHelpfull: Yes(0) No(0)
• Possible no of 1 digit numbers- 4.
  Possible no of 2 digit numbers- 4*3=12
  Possible no of 3 digit numbers -3*4*4= 48.
  So total numbers=(4+12+48)=64.
  
• 8 years agoHelpfull: Yes(0) No(1)