what is the probability of always having x+y>0 ,where y<0
a)1/2
b)1/8
c)3/4
d)1/4

• its d) 1/4
  total value of X can be : 1. X < 0 ; 2. X = 0 ; 3. X > 0 but less than Y in magnitude 4. X > 0 as well as |Y|
  so probability of having X + Y > 0 wud be 1/4
  
• 8 years agoHelpfull: Yes(12) No(4)
• x+(-y)>0=>x>y 50% chance 1/2
• 8 years agoHelpfull: Yes(5) No(1)
• 1/2 100% true
• 8 years agoHelpfull: Yes(4) No(2)
• here we have options for x being as..x>0 0r x=0 and there are no other options for x .thus reqd. probability = 1/2.
• 8 years agoHelpfull: Yes(2) No(2)
• how pritesh bhakat?
  
• 8 years agoHelpfull: Yes(1) No(0)
• b. becuse x+y>0 and y
• 8 years agoHelpfull: Yes(0) No(1)
• x can be - 1). x = y
  2). x > y
  3). x < y
  4). x = 0
  so x + y > 0 only if x > y
  hence, answer is 1/4 :-)
• 8 years agoHelpfull: Yes(0) No(2)
• 1/4 because x must be greater y and x must be greater than 0 . x>y and x >0 because suppose x is -1 and y is -2 then sum will be -3 which is less than 0
  
  so x>y and x>0. 1/2 * 1/2 = 1/4 ans.
  
• 8 years agoHelpfull: Yes(0) No(0)