2. What is the sum of the squares of the first 20 natural numbers (1 to 20)?

a) 2870

b) 2000

c) 5650

d) 44100

• n(n+1)(2n+1)/6
  20(21)(21)/6
  =2870
• 9 years agoHelpfull: Yes(13) No(7)
• it will be option a. using the formula n*(n+1)*(2n+1)/6 => 20*21*41/6=2870
• 9 years agoHelpfull: Yes(9) No(1)
• The sum of squares in natural n is=n(n+1)(2n+1)/6
  i,e=20*21*41/6
  =2870
  
• 9 years agoHelpfull: Yes(2) No(0)
• use sum of squares Formula:n*(n+1)*(2n+1)/6
  n=20,answer=2870 (option A)
• 9 years agoHelpfull: Yes(1) No(1)
• n/6*(n+1)*(2n+1)=2870
• 9 years agoHelpfull: Yes(1) No(0)
• it will be option a. using the formula n*(n+1)*(2n+1)/6 => 20*21*41/6=2870
• 9 years agoHelpfull: Yes(0) No(0)
• Use this formula n*n+1*2*n+1/6
  so ans is 2870
• 9 years agoHelpfull: Yes(0) No(0)
• sum=n(n+1)(2n+1)/6=2870
• 9 years agoHelpfull: Yes(0) No(1)
• 20(21)(21)/6=2870
  
• 9 years agoHelpfull: Yes(0) No(1)
• a sum of the squares formula n(n+1)(2n+1)/6
• 9 years agoHelpfull: Yes(0) No(0)
• n(n+1)(2n+1)/6
  =20*21*41/6
  =2870
• 9 years agoHelpfull: Yes(0) No(0)
• n(n+1)(2n+1)/6
• 9 years agoHelpfull: Yes(0) No(0)
• n(n+1)(2n+1)/6
  20(20+1)(41)/6
  =2870
• 9 years agoHelpfull: Yes(0) No(0)
• a...2870.........n(n+1)(2n+1)/6....
• 9 years agoHelpfull: Yes(0) No(0)
• sum of squares of first n natural number is n(n+1)(2n+1)/6
  so n=20
  if we substitute we'll get 2870 as ans
• 9 years agoHelpfull: Yes(0) No(0)
• 1+10=55
  11+20=155
  55+155=210
  210^2=44100
• 9 years agoHelpfull: Yes(0) No(1)
• 1/6*n*(n+1)*(2n+1)....20*21*41/6
• 9 years agoHelpfull: Yes(0) No(0)
• a..by using formula n(n+1)(2n+1)/6
• 9 years agoHelpfull: Yes(0) No(0)
• answer is 2870
• 9 years agoHelpfull: Yes(0) No(2)
• sum of squares of first n natural nos=(n(n+1)(2n+1))/6
  so required sum=(20(20+1)(2*20+1))/6=2870
• 9 years agoHelpfull: Yes(0) No(0)
• Use the formula for the summation of squares of first n natural numbers: n(n+1)(2n+1)/6
  On substituting the value of n as 20 in this case, we get the answer as 2870.
• 8 years agoHelpfull: Yes(0) No(0)
• option a is the answer
  sum of squares of 1st n natural numbers={n*(2n+1)*(n+1)}/6
  ={20*21*41}/6
  =2870
• 7 years agoHelpfull: Yes(0) No(0)
• n(n+1)(2n+1)/6
  20(21)(21)/6
  =2870
• 6 years agoHelpfull: Yes(0) No(0)
• n(n+1)(2n+1)/6
  20(21)(21)/6
  =2870
• 6 years agoHelpfull: Yes(0) No(0)
• The sum of squares of n natural numbers is:=n*(n+1)*(2 n+1)/6
  =>20*(20+1)*(2*20+1)/6
  =>(20*21*41)/6
  =2870
• 4 years agoHelpfull: Yes(0) No(0)