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Numerical Ability
Ratio and Proportion
Three containers A, B and C are having mixtures of milk and water in the ratio of 1:5, 3:5, 5:7 respectively. If the capacities of the containers are in the ratio 5:4:5, find the ratio of milk to water, if all the three containers are mixed together.
a. 53:115 b. 53:113
c. 54:115 d. 54:113
Read Solution (Total 10)
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- A) 53:115
let, capacities = 500,400,500 respectively
then new ratio= (1/6*500+3/8*400+5/12*500):(5/6*500+5/8*400+7/12*500)
=53:115 - 8 years agoHelpfull: Yes(25) No(5)
- milk=5*1/6 + 4*3/8 + 5*5/12
water=5*5/6 + 4*5/8 + 5*7/12
milk:water=53:115 - 8 years agoHelpfull: Yes(21) No(0)
- ((5*1/6)+(4*3/8)+(5*5/7))/5+4+5=53/168
53:(168-53)=53:115
a is the answer - 8 years agoHelpfull: Yes(16) No(8)
- @BISWAJIT & ROHIT :
IN THE QUESTION THE RATIOS ARE GIVEN AS 1:5, 3:5 , 5:7
THEN FRM WER DID U GT THE RATIOS 1/6 & 3/8?? - 8 years agoHelpfull: Yes(4) No(10)
- Weighted average rule can be applied = 5×16+4×38+5×5125+4+5 = 53168
So milk and water concentration = 53 : (168 - 53) = 53 : 115
- 8 years agoHelpfull: Yes(4) No(1)
- qauntity of milk in mixture=(1/6)*5+(3/8)*4+(5/12)*5=53/12
similary find for water content in final mixture that will be=106/24
so answer will 53:115 - 8 years agoHelpfull: Yes(1) No(1)
- amount of milk in total compund =(5*1/6+4*3/8+5*7/12)/(5+4+5)=53/168.
ratio of milk and water=53/(168-53)=53/115 - 6 years agoHelpfull: Yes(0) No(0)
- In container A
Milk=5x1/6 =5/6 water=5x5/6= 25/6
in container B
milk=4x3/8 =12/8 water = 4x5/8 =20/8
incontainer C
milk= 5x5/12 = 25/12 water 5x7/12 =35/12
total milk in NEW container
5/6+12/8+25/12= 53/12
and water = 25/6+ 20/8+35/12=115/12
ratio= 53:115 - 5 years agoHelpfull: Yes(0) No(0)
- ans is 53:115
- 4 years agoHelpfull: Yes(0) No(1)
- Can anyone explain from where we are getting 1/6, 3/8?
- 3 years agoHelpfull: Yes(0) No(0)
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