Three runners A, B and C run a race, with runner A finishing 12 meters ahead of runner B and 18 meters ahead of
runner C, while runner B finishes 8 meters ahead of runner C. Each runner travels the entire distance at a constant
speed. What was the length of the race?
a)36 meters b)48 meters c)60 meters d)72 meters

• Ans: 48M
  Let the length of race is X meter.
  when A is on X meter, then B is on X-12 and C is on X-8.
  Now,
  if B is on X-12 meter then C is on X-18 meter
  so if B is on 1 meter then C is on (X-18)/(X-12) meter
  So if B is on X meter then C is on ((X-18)/(X-12))*X meter
  and it is given that if B is on X meter then C is on X-8 meter
  So ((X-18)/(X-12))*X = X-8
  Solve it and get the value of X as 48 meter
  
• 8 years agoHelpfull: Yes(19) No(1)
• Let distance of race be x mtrs. Then when A finishes x m , B has run (x- 12)mtrs and C has run x-18 mtrs. so at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, so he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.
  
  as speeds are constant, we have equation,
  
  x-12/ x-18 = 12/10 > x = 48.
  
  Answer B
• 7 years agoHelpfull: Yes(3) No(1)
• answer id B
• 8 years agoHelpfull: Yes(1) No(4)
• ans is d.
  
• 8 years agoHelpfull: Yes(0) No(10)