Elitmus
Exam
Category
XAD
XSE
---------
WSPW
DEWK-
APHW--
-------------
ZEAPPW
Read Solution (Total 7)
-
- 8 6 4
8 5 3
-------------
2 5 9 2
4 3 2 0 -
6 9 1 2 - -
-------------
7 3 6 9 9 2
- 9 years agoHelpfull: Yes(8) No(1)
- 864
853
------------
2592
4320
6912
------------
736992
hint-
P+k = P so k=0 and S=5.
now E*D=W and X*D = W so W=2 and E=3,X= 8 and D=4 and so on. - 9 years agoHelpfull: Yes(7) No(0)
- 1. p+K=p means k=0; and we see that XAD*S= _ _ _ K and XAD*E=__ __ __w and XAD*X=__ __ __w so we can say that s=5(sure)
2. Now Take D=4 and (e,x)=(3 ,8 ) to make w=2 let X=8 and E=3 so w=2
3. (__ A __* S(5) ) +2( carry ) =__2 so A must be equal to 6 ie. A=6
4. Now S+ W+ W=p ie. 5+2+2=9(P) so p=9
5. proceed in the same way then fianlly we get
864 *853=
2592
4320
6912
________________________________
736992
________________________________
- 9 years agoHelpfull: Yes(3) No(0)
- here
p+k=p=>k=0 and so s*d=w0=>either s or d = 5 but when we choose d as 5
w must be 0 which is not possible so s=5
now
XAD*E=W5PW and XAD*X=APHW => we should have two pair such that D*E and D*X=W and E*X+carry=W5
here is no any possibe combination for W=1
and for W =2
we hav 4*3 and 4*8
so D=4 and w=2
here we choose E=3 and X=8
and we have solution
864*853=(2592+4320_+6912__)=736992 - 9 years agoHelpfull: Yes(1) No(0)
- 8 6 4
8 5 3
---------------------
2 5 9 2
4 3 2 0-
6 9 1 2--
---------------------
7 3 6 9 9 2 - 9 years agoHelpfull: Yes(0) No(1)
- 864
853
.......
2592
4320
6912
...........
736992 - 9 years agoHelpfull: Yes(0) No(0)
- 8 6 4
8 5 3
--------------
2 5 9 2
4 3 2 0 -
6 9 1 2 - -
---------------------
7 3 6 9 9 2 - 9 years agoHelpfull: Yes(0) No(0)
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