3 dice arerolled what is the probability of sum of the number on the faces being 10

• Always remember when 3 dice are rolled the number of ways of getting n ( where n is the sum of faces on dice)
  = (n−1)C2 where n = 3 to 8
  = 25 where n = 9, 12
  = 27 where n = 10, 11
  = (20−n)C2 where n = 13 to 18
  The required probability = 27/6^3 = 27/216
• 9 years agoHelpfull: Yes(7) No(0)
• Total possibilities = 6*6*6
  
  Now events where sum of three = 10 are :-
  
  1 3 6 ------ 6 possibilities
  1 4 5 ------ 6 possibilities
  2 2 6 ------ 3 possibilities
  2 3 5 ------ 6 possibilities
  2 4 4 ------ 3 possibilities
  3 3 4 ------ 3 possibilities
  
  hence probability = 27/216
• 9 years agoHelpfull: Yes(4) No(1)
• no. of sample space=216
  no.of event=39
  probability=39/216
  =0.18
• 9 years agoHelpfull: Yes(0) No(4)