the number of perfect cubes between 1 to 1000009 which are exactly divisible by 9

• 100^3=1000000
  then max limit=99,which is divided by 9
  in 1-100 there are 33 element which are divisible by 3.
  as well as there cubes also divisible by 9(3^3=9).
  so, the ans is 33.
• 8 years agoHelpfull: Yes(0) No(0)