sunil start from home at 4 pm and reaches school everyday at 5pm to pick up his children.on saturday the school got over ai 4 pm and children started walking towards home.sunil met them on the way and returned home 15min early.if speed of sunil is 35km/hr then for how many min did children walk? what is speed of children???

• sunil reach 15 min early. it is time save at both for going to school and coming to home.
  so, sunil meet children befor 15/2= 7.5 min.
  speed of sunil is 35km/hr i.e. 583.33 m/min.
  remaining distance to cover by sunil or else we can say total distance cover by children is 7.5*583.33=4375 m
  Sunil meet children after 52.5 min i.e. (1hr-7.5min).
  so 4375 is distance cover by children in 52.5min.
  so, speed of children is 4375/52.5=83.33m/min=5 km/hr.
• 9 years agoHelpfull: Yes(23) No(11)
• Total distanc trtravelled from home to school and then to home by sunil= 2x
  And on saturday he meets at a distance of y from his home
  So total distancte travelled=2y
  
  Total distance traveeled by children =x-y
  
  THe speed of children=speed of children
  The speed of sunil =speed of sunil
  
  So,(( x-y)/sped of children)=15/60
  (2x/35)=2
  (2y/35)=7/4
  After solving this 3 eqation
  We get
  Speed of children =35/2
• 9 years agoHelpfull: Yes(2) No(6)
• speed of sunil =35km/hr
  time taken by sunil=1hr
  so distance=35 km
  time taken by children=45min=3/4 hr
  therefore speed=35*4/3=140/3km/hr
  
• 9 years agoHelpfull: Yes(2) No(3)
• speed of children=5 km/hr
  children walked for 210 min
• 9 years agoHelpfull: Yes(1) No(0)
• Sunil goes 1hr 35 km so school distance 35 km
  Sunil travel as 35×(45/60)=105÷4 @45min
  15/60of sunil=45÷60 childern tavel
  Childrens travel 35÷4@45 min
  8.25km distance covered 45min
  8.25÷3 got 2.615×4=10.46km
• 6 years agoHelpfull: Yes(1) No(0)
• Please some one explain this question properly.
• 6 years agoHelpfull: Yes(0) No(1)