There is a rectangular Garden whose length and width is 60m X 20m There is a walkway of uniform width

let the width of rectangle be x
so the length & breath is increased by 2x(draw on a paper
then only u'll understand)
so new total area along with walkway is (60+2x)*(20+2x)
so (60+2x)*(20+2x)-60*20=516
=>(60+2x)*(20+2x)=1716
=>(30+x)*(10+x)=429=33*13
=>x=3
8 years agoHelpfull: Yes(8) No(7)
area of rect=60*20=1200
area of walk path=area of rect-area of remaining
516=(60*20)-((60-2x)*(20-2x))
x=3
8 years agoHelpfull: Yes(5) No(2)
mr. Bhanu and rahul. why you taken length and breadth is increased by 2x. can u explain and can u draw on paper and show it once.
8 years agoHelpfull: Yes(2) No(4)
mr dinesh is bcoz the rectangle is a 4 sided figure so 2 breath and 2 length but why -60*20 again in the solution plz explain
8 years agoHelpfull: Yes(2) No(1)
Let width of walkway is w
20*w + 20*w + 60*w + 60*w + 4*w*w = 516
w =3
8 years agoHelpfull: Yes(2) No(1)
mr laxman its becoz we can get walkway area by subtracting entire garden with walkway(i.e (60+2x)*(20+2x)) with only garden area(i.e 60*20).
8 years agoHelpfull: Yes(0) No(2)

There is a rectangular Garden whose length and width is 60m X 20m.There is a walkway of uniform
width around garden. Area of walkway is 516m2. Find width of walkway?