if there are diffrent kind of burger in that some 1st 5th 9th... so on contain mashroom and 2nd 9th 16th ... and so on contain chillies. while 1st 5th 9th...contain chilly ... while other burgers contain butter ....if there is machine which produce 660 burgers then find nuber of burgers which contain butter....

a. 350 b. 400 c.450 d.500

• b. 400
  check out the 1st series which contain mashroom 1,5,9 it means difference of 4 hence, 660/4=165
  also 2nd series which contain chillies 2,9,15...difference is 7 so 94 burgers
  now other burgers which contain butter= 660-(165+94)= 401 app. 400
  
• 9 years agoHelpfull: Yes(12) No(3)
• 1,5,9____660 contains 165 terms.
  2,7,8-----660 contains 98 terms
  9,65,--- are common. hence they are 12 terms.
  total butter burger =660-(165+98-12)=349=350(approx)
• 9 years agoHelpfull: Yes(4) No(0)
• 1st 5th 9th...so on
  in this series only 1st 5th 9th contain chilly while other butter
  hence 660-((660/4)-3)=660-(165-3)=660-162=498 (approx 500)
  ans is D
• 9 years agoHelpfull: Yes(2) No(1)
• sorry guys check the answer... answer is not exactly corrrect..
  
• 9 years agoHelpfull: Yes(0) No(1)
• 1,5,9-------660----->mashroom
  660=1+(n-1)4
  n=663/4
  2,9,16-----660------>chillies
  660=2+(n-1)7
  n=665/7
  butter=660-((663)/4+(665/7))
  
• 9 years agoHelpfull: Yes(0) No(1)
• 660 -(660/4 +660/7+660/47)
  =165+94-14
  =415
  so 400 ans
• 9 years agoHelpfull: Yes(0) No(1)